http://www.pimp-your-poker.com/how-poker-chips-are-made/
Induction question?
Hi, I've Been Looking For in this last week now and I still have no idea how to do it! Can I someone help? Q. A Poker Club playing with blue chips worth $ 5 and red chips worth $ 8 What is to be the largest that can not be done? (Note – Use induction) ————————- Here is what I have: done So far Want to find the largest n such that n ≠ 5x + 8y, where x and y are all Numbers greater than or equal to zero. It looks like it contains complete induction. Test: n = 1 – n = 2 Yes – yes … n = 5 – no n = 6 – yes n = 7 – n = 8 yes – no List … seems to go on indefinitely – not where I go from here?
Someone else turns Written this, and the answer to be $ as 27th The list goes on one way, but not unlimited. Here's why. A bet can be made if its value corresponds 5b 8R + for some non-negative integers b and r. A bet can be made as if either the bet $ 5 or less the wager 8 USD less, can be Made, because we only need to add the appropriate chip. Possible in terms of ordered pairs (b, r) betting, are: (0,0) = $ 0 (trivial case) (1.0) = $ 5 (minimum 1-chips, $ 1, $ 2, $ 3 , $ 4 can not can be bet) (0.1) = $ 8 (2,0) = $ 10 (minimum two chips, then $ 6, $ 7, $ 9 't bet) (1,1) = $ 13 (0, 2) = $ 16 (3,0) = $ 15 (smallest 3-chip, so $ 11, $ 12, $ 14 can not be wagered) (2,1) = $ 18 (1.2) = $ 21 (0.3) = $ 24 (4.0 ) = $ 20 (smallest four-chip so $ 17, $ 19 can not be wagered) (3.1) = $ 23 (2.2) = $ 26 (1.3) = $ 29 (0, 4) = $ 32 (5.0) = $ 25 (minimum 5 chips, so $ 22 can not bet) (4.1) = $ 28 (3,2) = $ 31 (2.3) = $ 34 (1.4) = $ 37 (0,5) = $ 40 (6,0) = $ 30 (minimum 6-chips, so $ 27 can not bet) But now we see that it is possible to 31 bet $ 28, $ 29, $ 30, $ and $ 32, and all the higher dollar amount may, by adding $ 5 Chips in the combinations, so $ 27 is made to the highest amount bet on the dollar can not.
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