http://www.pimp-your-poker.com/poker-hands-greatest-to-least/
can someone answer these other problems?
1. A pair of dice is thrown. Find the probability of a) a total of 8? B) Not more than a total of 5? 2.Two cards are successively drawn from a deck without replacement. What is the probability that both cards are 8 larger than 2 and less than? 3. If each element coded in the catalog starts with 5 different characters and 3 different numbers from zero, where the probability of randomly selecting one of these terms encoded by the first Letters of a vowel and the last digit, too? 4.In a poker hand of cards, where he likely uptake of 3 Aces? 5.In a poker game where a player is dealt cards 5 from a stack of 53 cards (52 cards + 1 Joker), which is the probability that a full house? 6.From a group of 8 and 6 mathematician physicist, a committee consisting to be formed of 5 members. What is the probability of the formation of a committee that includes at least two mathematicians and physicists at least 1?
1a. It are 7 ways to have an 8: 71 17 26 35 44 53 62 So the probability 7 / 36 1b. There are 10 ways to a maximum total of 5: 11, 12, 21, 13, 22, 31, 14, 23, 32, 41, probably as 10/36 = 18.5 is 2. There are 5 cards in each color greater than 2 but less than 8, so that the probability The first card, there are 5 / 13 The probability of the second card is greater than 2 and less than 8 (20-1) / 52 = 19/52, as there is no substitute. So the probability (5 / 13) * (19/52) = 95/676. 3. There are 26 * 25 * 24 * 23 * 22 * 9 * 8 * 7 different codes. There are 5 * 25 * 24 * 23 * 22 * 4 * 8 * 7 different codes with the first letter of a vowel and the last digit too. So the chance: 5 * 25 * 24 * 23 * 22 * 4 * 8 * 26.7 * 25 * 24 * 23 * 22 * 9 * 8 * 7 = 26.5 * 9.4 = 10/117. 4. I assume you meant 5 cards. There are (4 choose 3) * (49 choose 2) hands with 3 aces. There are (52 choose 5) hands all together. So the probability: (4 choose 3) * (49 choose 2) / (52 choose 5) = 2 / 1105 5th. There are (13 choose 2) * 2 * (4 choose 3) * (4 choose 2) = 3744 full houses without a joker (choose 2 ranks and then added the 3 cards, and has 2, then select 3 is possible by the 4, and 2 of the 4 possible for each rank). (Select 4 2) There are (13 choose 2) * * = 2808 full houses (4 2) choose a Joker (choose 2 ranks, then select 2 cards of each rank). For a total of 6552 full houses. There are (53 choose 5) = 2,869,685 hands. So the probability is 6552/286985 = 72 / 31535 or about 0.2283% 6 Find out how many committees less than 2 mathematicians or physicists contain less than 1. There are (choose 8 choose 1) * (6 4) = 120 committees with a mathematician, and (6 choose 5) = 6 committees with 0 mathematician, and there are (8 choose 5) = 56 Committees with 0 physicists. There are 182 total committees meet so do not have the condition. There are committees = 2002 (14 choose 5) total. So the defined probability with at least 2 of mathematicians and physicists at least 1 of 1 – 182/2002 = 10/11.
Greatest Poker Hands Ever
